添加Go语言题解

animation-simulation/求和问题/三数之和.md

@@ -162,3 +162,52 @@ class Solution {
     }
 }
 ```
+
+
+Go Code:
+
+```go
+func threeSum(nums []int) [][]int {
+    res := [][]int{}
+    length := len(nums)
+    if length < 3 {
+        return res
+    }
+
+    sort.Ints(nums)
+    for i := 0; i < length - 2; i++ {
+        // 去重
+        if i != 0 && nums[i] == nums[i - 1] {
+            continue
+        }
+        l, r := i + 1, length - 1
+        for l < r {
+            /*
+            // 下面两个for循环的去重也可以用下面的代码替换
+            if l != i + 1 && nums[l] == nums[l - 1] {
+                l++
+                continue
+            }
+            */
+            if nums[i] + nums[l] + nums[r] == 0 {
+                res = append(res, []int{nums[i], nums[l], nums[r]})
+                for l < r && nums[l] == nums[l + 1] {
+                    l++
+                }
+                for l < r && nums[r] == nums[r - 1] {
+                    r--
+                }
+                l++
+                r--
+            } else if nums[i] + nums[l] + nums[r] < 0 {
+                l++
+            } else {
+                r--
+            }
+
+        }
+    }
+    return res
+}
+```
+

animation-simulation/求和问题/两数之和.md

@@ -54,6 +54,21 @@ class Solution {
 }
 ```
 
+Go Code:
+
+```go
+func twoSum(nums []int, target int) []int {
+    m := make(map[int]int)
+    for i, num := range nums {
+        if v, ok := m[target - num]; ok {
+            return []int{v, i}
+        }
+        m[num] = i
+    }
+    return []int{}
+}
+```
+
 ### 双指针（暴力）法
 
 #### 解析

animation-simulation/求和问题/四数之和.md

@@ -95,3 +95,61 @@ class Solution {
     }
 }
 ```
+
+
+Go Code:
+
+```go
+func fourSum(nums []int, target int) [][]int {
+    res := [][]int{}
+    length := len(nums)
+    if length < 4 {
+        return res
+    }
+
+    sort.Ints(nums)
+    for i := 0; i < length - 3; i++ {
+        // 去重
+        if i != 0 && nums[i] == nums[i - 1] {
+            continue
+        }
+        for j := i + 1; j < length - 2; j++ {
+            // 去重
+            if j != i + 1 && nums[j] == nums[j - 1] {
+                continue
+            }
+            l, r := j + 1, length - 1
+            for l < r {
+                /*
+                // 下面两个for循环的去重也可以用下面的代码替换
+                if l != i + 1 && nums[l] == nums[l - 1] {
+                    l++
+                    continue
+                }
+                */
+                sum := nums[i] + nums[j] + nums[l] + nums[r]
+                if sum == target {
+                    res = append(res, []int{nums[i], nums[j], nums[l], nums[r]})
+                    for l < r && nums[l] == nums[l + 1] {
+                        l++
+                    }
+                    for l < r && nums[r] == nums[r - 1] {
+                        r--
+                    }
+                    l++
+                    r--
+                } else if sum < target {
+                    l++
+                } else {
+                    r--
+                }
+
+            }
+        }
+    }
+    return res
+}
+```
+
+
+