Update 堆排序.md

去掉堆排序多申请的数组
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@ -219,40 +219,39 @@ def sink(nums: list, index: int, len: int):
Java Code:
```java
class Solution {
public class Solution {
int rollBack(int i) {
return i - 1;
}
public int[] sortArray(int[] nums) {
int len = nums.length;
int[] a = new int[len + 1];
for (int i = 0; i < nums.length; ++i) {
a[i+1] = nums[i];
}
//下沉建堆
for (int i = len/2; i >= 1; --i) {
sink(a,i,len);
for (int i = len / 2; i >= 1; --i) {
sink(nums, i, len);
}
int k = len;
//排序
while (k > 1) {
swap(a,1,k--);
sink(a,1,k);
}
for (int i = 1; i < len+1; ++i) {
nums[i-1] = a[i];
swap(nums, 1, k--);
sink(nums, 1, k);
}
return nums;
}
public void sink (int[] nums, int k,int end) {
public void sink(int[] nums, int k, int end) {
//下沉
while (2 * k <= end) {
int j = 2 * k;
//找出子节点中最大或最小的那个
if (j + 1 <= end && nums[j + 1] > nums[j]) {
if (j + 1 <= end && nums[rollBack(j + 1)] > nums[rollBack(j)]) {
j++;
}
if (nums[j] > nums[k]) {
if (nums[rollBack(j)] > nums[rollBack(k)]) {
swap(nums, j, k);
} else {
break;
@ -260,10 +259,11 @@ class Solution {
k = j;
}
}
public void swap (int nums[], int i, int j) {
int temp = nums[i];
nums[i] = nums[j];
nums[j] = temp;
void swap(int[] nums, int i, int j) {
int temp = nums[rollBack(i)];
nums[rollBack(i)] = nums[rollBack(j)];
nums[rollBack(j)] = temp;
}
}
@ -272,39 +272,40 @@ class Solution {
Python Code:
```python
def rollBack(i: int):
return i - 1
def sortArray(nums: list)->list:
leng = len(nums)
a = [0] + nums
# 下沉建堆
for i in range(int(leng / 2), 0, -1):
sink(a, i, leng)
sink(nums, i, leng)
k = leng
# 排序
while k > 1:
swap(a, 1, k)
swap(nums, 1, k)
k -= 1
sink(a, 1, k)
sink(nums, 1, k)
for i in range(1, leng + 1):
nums[i - 1] = a[i]
return nums
def swap(nums: list, i: int, j: int):
temp = nums[i]
nums[i] = nums[j]
nums[j] = temp
temp = nums[rollBack(i)]
nums[rollBack(i)] = nums[rollBack(j)]
nums[rollBack(j)] = temp
def sink(nums: list, k: int, end: int):
while 2 * k <= end:
j = 2 * k
if j + 1 <= end and nums[j + 1] > nums[j]:
if j + 1 <= end and nums[rollBack(j + 1)] > nums[rollBack(j)]:
j += 1
if nums[j] > nums[k]:
if nums[rollBack(j)] > nums[rollBack(k)]:
swap(nums, j, k)
else:
break
k = j
```
好啦堆排序我们就到这里啦是不是搞定啦总的来说堆排序比其他排序算法稍微难理解一些重点就是建堆而且应用比较广泛大家记得打卡呀