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Merge pull request #22 from daluozha/main
leetcode 160、328,剑指offer22 补充js代码
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commit
6b59314ce4
@ -89,3 +89,19 @@ public:
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};
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```
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JS Code:
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```javascript
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var oddEvenList = function(head) {
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if(!head || !head.next) return head;
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let odd = head, even = head.next, evenHead = even;
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while(odd.next && even.next){
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odd.next = even.next;
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odd = odd.next;
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even.next = odd.next;
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even = even.next;
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}
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odd.next = evenHead;
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return head;
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};
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```
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@ -79,6 +79,24 @@ public:
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};
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```
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JS Code:
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```javascript
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var getIntersectionNode = function(headA, headB) {
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let tempa = headA, tempb = headB
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const map = new Map()
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while(tempa){
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map.set(tempa, 1)
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tempa = tempa.next
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}
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while(tempb){
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if(map.get(tempb))
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return tempb
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tempb = tempb.next
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}
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return tempb
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};
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```
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下面这个方法比较巧妙,不是特别容易想到,大家可以自己实现一下,这个方法也是利用我们的双指针思想。
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下面我们直接看动图吧,特别直观,一下就可以搞懂。
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@ -128,6 +146,18 @@ public:
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};
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```
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JS Code:
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```javascript
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var getIntersectionNode = function(headA, headB) {
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let tempa = headA, tempb = headB
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while(tempa !== tempb){
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tempa = tempa ? tempa.next : headB
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tempb = tempb ? tempb.next : headA
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}
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return tempa
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};
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```
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好啦,链表的题目就结束啦,希望大家能有所收获,下周就要更新新的题型啦,继续坚持,肯定会有收获的。
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@ -93,3 +93,18 @@ public:
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};
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```
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JS Code:
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```javascript
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var getKthFromEnd = function(head, k) {
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if(!head) return head;
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let pro = head, after = head;
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for(let i = 0; i < k - 1; i++){
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pro = pro.next;
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}
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while(pro.next){
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pro = pro.next;
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after = after.next;
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}
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return after;
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};
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```
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