为数组篇 增加 Swift 实现

This commit is contained in:
zhenzi
2021-07-17 12:13:15 +08:00
parent 2c4afffbd3
commit c14c2297f1
14 changed files with 702 additions and 1 deletions

View File

@@ -96,6 +96,38 @@ class Solution:
nums[j] = temp
```
Swift Code:
```swift
class Solution {
func sortColors(_ nums: inout [Int]) {
let count = nums.count
var left = 0, i = left, right = count - 1
while i <= right {
if nums[i] == 2 {
//nums.swapAt(i, right) 直接调用系统方法
self.swap(&nums, i, right) // 保持风格统一走自定义交换
right -= 1
} else if nums[i] == 0 {
//nums.swapAt(i, left) 直接调用系统方法
self.swap(&nums, i, left) // 保持风格统一走自定义交换
i += 1
left += 1
} else {
i += 1
}
}
}
func swap(_ nums: inout [Int], _ i: Int, _ j: Int) {
let temp = nums[i]
nums[i] = nums[j]
nums[j] = temp
}
}
```
另外我们看这段代码有什么问题呢那就是我们即使完全符合时仍会交换元素这样会大大降低我们的效率
例如[0,0,0,1,1,1,2,2,2]
@@ -174,4 +206,39 @@ class Solution:
temp = nums[i]
nums[i] = nums[j]
nums[j] = temp
```
Swift Code:
```swift
class Solution {
func sortColors(_ nums: inout [Int]) {
let count = nums.count
var left = 0, i = left, right = count - 1
while i <= right {
if nums[i] == 0 {
//nums.swapAt(i, left) 直接调用系统方法
self.swap(&nums, i, left) // 保持风格统一走自定义交换
left += 1
}
if nums[i] == 2 {
//nums.swapAt(i, right) 直接调用系统方法
self.swap(&nums, i, right) // 保持风格统一走自定义交换
right -= 1
//如果不等于 1 则需要继续判断,所以不移动 i 指针i--
if nums[i] != 1 {
i -= 1
}
}
i += 1
}
}
func swap(_ nums: inout [Int], _ i: Int, _ j: Int) {
let temp = nums[i]
nums[i] = nums[j]
nums[j] = temp
}
}
```