Add section of binary search tree.

Make all table align center.
This commit is contained in:
krahets 2022-11-15 04:55:19 +08:00
parent 7fdb4d1443
commit 2f8829d3f6
4 changed files with 160 additions and 2 deletions

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@ -0,0 +1,146 @@
package chapter_tree;
import java.util.*;
import include.*;
class BinarySearchTree {
private TreeNode root;
public BinarySearchTree(int[] nums) {
Arrays.sort(nums); // 排序数组
root = buildTree(nums, 0, nums.length - 1); // 构建二叉搜索树
}
/* 获取二叉树根结点 */
public TreeNode getRoot() {
return root;
}
/* 构建二叉搜索树 */
public TreeNode buildTree(int[] nums, int i, int j) {
if (i > j) return null;
// 将数组中间结点作为根结点
int mid = (i + j) / 2;
TreeNode root = new TreeNode(nums[mid]);
// 递归建立左子树和右子树
root.left = buildTree(nums, i, mid - 1);
root.right = buildTree(nums, mid + 1, j);
return root;
}
/* 查找结点 */
public TreeNode search(int num) {
TreeNode cur = root;
// 循环查找越过叶结点后跳出
while (cur != null) {
// 目标结点在 root 的右子树中
if (cur.val < num) cur = cur.right;
// 目标结点在 root 的左子树中
else if (cur.val > num) cur = cur.left;
// 找到目标结点跳出循环
else break;
}
// 返回目标结点
return cur;
}
/* 插入结点 */
public TreeNode insert(int num) {
// 若树为空直接提前返回
if (root == null) return null;
TreeNode cur = root, pre = null;
// 循环查找越过叶结点后跳出
while (cur != null) {
// 找到重复结点直接返回
if (cur.val == num) return null;
pre = cur;
// 插入位置在 root 的右子树中
if (cur.val < num) cur = cur.right;
// 插入位置在 root 的左子树中
else cur = cur.left;
}
// 插入结点 val
TreeNode node = new TreeNode(num);
if (pre.val < num) pre.right = node;
else pre.left = node;
return node;
}
/* 删除结点 */
public TreeNode remove(int num) {
// 若树为空直接提前返回
if (root == null) return null;
TreeNode cur = root, pre = null;
// 循环查找越过叶结点后跳出
while (cur != null) {
// 找到待删除结点跳出循环
if (cur.val == num) break;
pre = cur;
// 待删除结点在 root 的右子树中
if (cur.val < num) cur = cur.right;
// 待删除结点在 root 的左子树中
else cur = cur.left;
}
// 若无待删除结点则直接返回
if (cur == null) return null;
// 子结点数量 = 0 or 1
if (cur.left == null || cur.right == null) {
// 当子结点数量 = 0 / 1 child = null / 该子结点
TreeNode child = cur.left != null ? cur.left : cur.right;
// 删除结点 cur
if (pre.left == cur) pre.left = child;
else pre.right = child;
}
// 子结点数量 = 2
else {
// 获取中序遍历中 cur 的下一个结点
TreeNode nex = min(cur.right);
int tmp = nex.val;
// 递归删除结点 nex
remove(nex.val);
// nex 的值复制给 cur
cur.val = tmp;
}
return cur;
}
/* 获取最小结点 */
public TreeNode min(TreeNode root) {
if (root == null) return root;
// 循环访问左子结点直到叶结点时为最小结点跳出
while (root.left != null) {
root = root.left;
}
return root;
}
}
public class binary_search_tree {
public static void main(String[] args) {
/* 初始化二叉搜索树 */
int[] nums = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 };
BinarySearchTree bst = new BinarySearchTree(nums);
System.out.println("\n初始化的二叉树为\n");
PrintUtil.printTree(bst.getRoot());
/* 查找结点 */
TreeNode node = bst.search(5);
System.out.println("\n查找到的结点对象为 " + node + ",结点值 = " + node.val);
/* 插入结点 */
node = bst.insert(16);
System.out.println("\n插入结点 16 后,二叉树为\n");
PrintUtil.printTree(bst.getRoot());
/* 删除结点 */
bst.remove(1);
System.out.println("\n删除结点 1 后,二叉树为\n");
PrintUtil.printTree(bst.getRoot());
bst.remove(2);
System.out.println("\n删除结点 2 后,二叉树为\n");
PrintUtil.printTree(bst.getRoot());
bst.remove(4);
System.out.println("\n删除结点 4 后,二叉树为\n");
PrintUtil.printTree(bst.getRoot());
}
}

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@ -23,3 +23,5 @@ TODO
| 更新:列表 Java 代码、配图 | 2022-11-07 |
| 新增:栈与队列 | 2022-11-09 |
| 新增:树 | 2022-11-12 |
| 新增:二叉搜索树,<br />更新:二叉树、表格居中 | 2022-11-13 |
| 更新:二叉搜索树 | 2022-11-14 |

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@ -20,3 +20,13 @@
--md-typeset-color: #FEFEFE;
--md-typeset-a-color: #31BC5A;
}
/* Center Markdown Tables (requires md_in_html extension) */
.center-table {
text-align: center;
}
.md-typeset .center-table :is(td,th):not([align]) {
/* Reset alignment for table cells */
text-align: initial;
}

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@ -17,7 +17,7 @@ theme:
features:
- announce.dismiss
- content.code.annotate
# - content.tabs.link
- content.tabs.link
- content.tooltips
# - header.autohide
# - navigation.expand