sort
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		| @@ -1,37 +1,47 @@ | ||||
| ''' | ||||
| File: bubble_sort.py | ||||
| Created Time: 2022-11-25 | ||||
| Author: Krahets (krahets@163.com) | ||||
| Author: timi (xisunyy@163.com) | ||||
| ''' | ||||
|  | ||||
| import sys, os.path as osp | ||||
| sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__)))) | ||||
| from include import * | ||||
| import sys | ||||
| import os.path as osp | ||||
| sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__)))) | ||||
|  | ||||
| "冒泡排序" | ||||
| """冒泡排序""" | ||||
| def bubble_sort(nums): | ||||
|     n=len(nums) | ||||
|     n = len(nums) | ||||
|     # 外循环:待排序元素数量为 n-1, n-2, ..., 1 | ||||
|     for i in range(n-1,-1,-1): | ||||
|     for i in range(n-1, -1, -1): | ||||
|         # 内循环:冒泡操作 | ||||
|         for j in range(i): | ||||
|             if nums[j]>nums[j+1]: | ||||
|                 nums[j],nums[j+1]=nums[j+1],nums[j] | ||||
| "冒泡排序(标志优化)" | ||||
| def bubbleSortWithFlag(nums): | ||||
|     n=len(nums) | ||||
|             # 交换 nums[j] 与 nums[j + 1] | ||||
|             if nums[j] > nums[j+1]: | ||||
|                 nums[j], nums[j+1] = nums[j+1], nums[j] | ||||
|  | ||||
|  | ||||
| """冒泡排序(标志优化)""" | ||||
| def bubble_sort_with_flag(nums): | ||||
|     n = len(nums) | ||||
|     # 外循环:待排序元素数量为 n-1, n-2, ..., 1 | ||||
|     for i in range(n-1,-1,-1): | ||||
|         flag=False              #初始化标志位 | ||||
|     for i in range(n-1, -1, -1): | ||||
|         flag = False  # 初始化标志位 | ||||
|         # 内循环:冒泡操作 | ||||
|         for j in range(i): | ||||
|             if nums[j]>nums[j+1]: | ||||
|                 nums[j],nums[j+1]=nums[j+1],nums[j] | ||||
|                 flag=True       #记录交换元素 | ||||
|         if not flag:break | ||||
| if __name__=='__main__': | ||||
|     nums=[4,1,3,1,5,2] | ||||
|             # 交换 nums[j] 与 nums[j + 1] | ||||
|             if nums[j] > nums[j+1]: | ||||
|                 nums[j], nums[j+1] = nums[j+1], nums[j] | ||||
|                 flag = True  # 记录交换元素 | ||||
|         if not flag: | ||||
|             break  # 此轮冒泡未交换任何元素,直接跳出 | ||||
|  | ||||
|  | ||||
| if __name__ == '__main__': | ||||
|     nums = [4, 1, 3, 1, 5, 2] | ||||
|     bubble_sort(nums) | ||||
|     print("冒泡排序后数组 nums = " ,nums) | ||||
|     bubbleSortWithFlag(nums) | ||||
|     print("冒泡排序后数组 nums = " ,nums) | ||||
|     print("排序后数组 nums = ", nums) | ||||
|  | ||||
|     nums1 = [4, 1, 3, 1, 5, 2] | ||||
|     bubble_sort_with_flag(nums1) | ||||
|     print("排序后数组 nums = ", nums1) | ||||
|   | ||||
| @@ -1,26 +1,28 @@ | ||||
| ''' | ||||
| File: insertion_sort.py | ||||
| Created Time: 2022-11-25 | ||||
| Author: Krahets (krahets@163.com) | ||||
| Author: timi (xisunyy@163.com) | ||||
| ''' | ||||
|  | ||||
| import sys, os.path as osp | ||||
| sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__)))) | ||||
| from include import * | ||||
| import sys | ||||
| import os.path as osp | ||||
| sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__)))) | ||||
|  | ||||
| "直接插入排序" | ||||
| def insertionSort(nums): | ||||
|     #外循环:base = nums[1], nums[2], ..., nums[n-1] | ||||
|     for i in range(1,len(nums)): | ||||
|         base=nums[i] | ||||
|         j=i-1 | ||||
|         #内循环:将 base 插入到左边的正确位置 | ||||
|         while j>=0 and nums[j]>base: | ||||
|             nums[j+1]=nums[j]   #1. 将 nums[j] 向右移动一位 | ||||
|             j-=1 | ||||
|         nums[j+1]=base          #2. 将 base 赋值到正确位置 | ||||
| """插入排序""" | ||||
| def insertion_sort(nums): | ||||
|     # 外循环:base = nums[1], nums[2], ..., nums[n-1] | ||||
|     for i in range(1, len(nums)): | ||||
|         base = nums[i] | ||||
|         j = i-1 | ||||
|         # 内循环:将 base 插入到左边的正确位置 | ||||
|         while j >= 0 and nums[j] > base: | ||||
|             nums[j+1] = nums[j]  # 1. 将 nums[j] 向右移动一位 | ||||
|             j -= 1 | ||||
|         nums[j+1] = base  # 2. 将 base 赋值到正确位置 | ||||
|  | ||||
| if __name__=='__main__': | ||||
|     nums=[4,1,3,1,5,2] | ||||
|     insertionSort(nums) | ||||
|     print("排序后数组 nums = " ,nums) | ||||
|  | ||||
| if __name__ == '__main__': | ||||
|     nums = [4, 1, 3, 1, 5, 2] | ||||
|     insertion_sort(nums) | ||||
|     print("排序后数组 nums = ", nums) | ||||
|   | ||||
| @@ -1,48 +1,60 @@ | ||||
| ''' | ||||
| File: merge_sort.py | ||||
| Created Time: 2022-11-25 | ||||
| Author: Krahets (krahets@163.com) | ||||
| Author: timi (xisunyy@163.com) | ||||
| ''' | ||||
|  | ||||
| import sys, os.path as osp | ||||
| sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__)))) | ||||
| import copy | ||||
| from include import * | ||||
| import sys | ||||
| import os.path as osp | ||||
| sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__)))) | ||||
|  | ||||
|  | ||||
| """ | ||||
| 另一种 思路实现归并排序 | ||||
| 合并左子数组和右子数组 | ||||
| 左子数组区间 [left, mid] | ||||
| 右子数组区间 [mid + 1, right] | ||||
| """ | ||||
| def merge_sort(nums,l,r): | ||||
|     if l>=r:return  | ||||
|     mid=l+r>>1                  #划分中点 | ||||
|     #进行归并 | ||||
|     merge_sort(nums,l,mid) | ||||
|     merge_sort(nums,mid+1,r) | ||||
|  | ||||
|     k,i,j=0,l,mid+1             #借助辅助数组 完成排序 | ||||
|     while i<=mid and j<=r:   | ||||
|         if nums[i]<=nums[j]:    #这一步保证了 稳定排序 | ||||
|             help_ls[k]=nums[i] | ||||
|             i+=1 | ||||
| def merge(nums, left, mid, right): | ||||
|     # 初始化辅助数组 借助 copy模块 | ||||
|     tmp = copy.deepcopy(nums[left:right+1]) | ||||
|     # 左子数组的起始索引和结束索引 | ||||
|     leftStart, leftEnd = left-left, mid - left | ||||
|     # 右子数组的起始索引和结束索引 | ||||
|     rightStart, rightEnd = mid + 1 - left, right - left | ||||
|     # i, j 分别指向左子数组、右子数组的首元素 | ||||
|     i, j = leftStart, rightStart | ||||
|     # 通过覆盖原数组 nums 来合并左子数组和右子数组 | ||||
|     for k in range(left, right+1): | ||||
|         # 若 “左子数组已全部合并完”,则选取右子数组元素,并且 j++ | ||||
|         if i > leftEnd: | ||||
|             nums[k] = tmp[j] | ||||
|             j += 1 | ||||
|         # 否则,若 “右子数组已全部合并完” 或 “左子数组元素 < 右子数组元素”,则选取左子数组元素,并且 i++ | ||||
|         elif j > rightEnd or tmp[i] <= tmp[j]: | ||||
|             nums[k] = tmp[i] | ||||
|             i += 1 | ||||
|         # 否则,若 “左子数组元素 > 右子数组元素”,则选取右子数组元素,并且 j++ | ||||
|         else: | ||||
|             help_ls[k]=nums[j] | ||||
|             j+=1 | ||||
|         k+=1 | ||||
|             nums[k] = tmp[j] | ||||
|             j += 1 | ||||
|  | ||||
|     while i<=mid:               #对于左边区域 | ||||
|         help_ls[k]=nums[i] | ||||
|         k,i=k+1,i+1 | ||||
|     while j<=r:                 #对于右边区域 | ||||
|         help_ls[k]=nums[j] | ||||
|         k,j=k+1,j+1 | ||||
|  | ||||
|     i,j=l,0 | ||||
|     while i<=r: | ||||
|         nums[i]=help_ls[j] | ||||
|         i,j=i+1,j+1 | ||||
| if __name__=='__main__': | ||||
|     nums=[4,1,3,1,5,2] | ||||
|     n=len(nums) | ||||
|     help_ls=[0 for _ in range(n)] | ||||
|     merge_sort(nums,0,n-1) | ||||
|     print("归并排序完成后 nums = ",nums) | ||||
| """归并排序""" | ||||
| def merge_sort(nums, left, right): | ||||
|     # 终止条件 | ||||
|     if left >= right: | ||||
|         return            # 当子数组长度为 1 时终止递归 | ||||
|     # 划分阶段 | ||||
|     mid = left + right >> 1  # 计算中点 | ||||
|     merge_sort(nums, left, mid)         # 递归左子数组 | ||||
|     merge_sort(nums, mid + 1, right)    # 递归右子数组 | ||||
|     # 合并阶段 | ||||
|     merge(nums, left, mid, right) | ||||
|  | ||||
|  | ||||
| if __name__ == '__main__': | ||||
|     nums = [4, 1, 3, 1, 5, 2] | ||||
|     merge_sort(nums, 0, len(nums)-1) | ||||
|     print("归并排序完成后 nums = ", nums) | ||||
|   | ||||
| @@ -1,31 +1,132 @@ | ||||
| ''' | ||||
| File: quick_sort.py | ||||
| Created Time: 2022-11-25 | ||||
| Author: Krahets (krahets@163.com) | ||||
| Author: timi (xisunyy@163.com) | ||||
| ''' | ||||
|  | ||||
| import sys, os.path as osp | ||||
| sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__)))) | ||||
| from include import * | ||||
| import sys | ||||
| import os.path as osp | ||||
| sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__)))) | ||||
|  | ||||
|  | ||||
| "另一种思维 实现快速排序" | ||||
| def quick_sort(nums,l,r): | ||||
|     if l>=r: | ||||
|         return  | ||||
|     i,j,x=l-1,r+1,nums[l+r>>1] | ||||
|     while i<j: | ||||
|         while True: | ||||
|             i+=1 | ||||
|             if nums[i]>=x:break | ||||
|         while True: | ||||
|             j-=1 | ||||
|             if nums[j]<=x:break | ||||
|         if i<j:nums[i],nums[j]=nums[j],nums[i] | ||||
|     quick_sort(nums,l,j),quick_sort(nums,j+1,r) | ||||
| if __name__=='__main__': | ||||
|     nums=[4,1,3,1,5,2] | ||||
|     n=len(nums) | ||||
|     help_ls=[0 for _ in range(n)] | ||||
|     quick_sort(nums,0,n-1) | ||||
|     print("快速排序完成后 nums = ",nums) | ||||
| """快速排序类""" | ||||
| class quick_sort(object): | ||||
|  | ||||
|     """哨兵划分""" | ||||
|     def partition(self, nums, left, right): | ||||
|         # 以 nums[left] 作为基准数 | ||||
|         i, j = left, right | ||||
|         while i < j: | ||||
|             while i < j and nums[j] >= nums[left]: | ||||
|                 j -= 1   # 从右向左找首个小于基准数的元素 | ||||
|             while i < j and nums[i] <= nums[left]: | ||||
|                 i += 1   # 从左向右找首个大于基准数的元素 | ||||
|             # 元素交换 | ||||
|             nums[i], nums[j] = nums[j], nums[i] | ||||
|         # 将基准数交换至两子数组的分界线 | ||||
|         nums[i], nums[left] = nums[left], nums[i] | ||||
|         return i  # 返回基准数的索引 | ||||
|  | ||||
|     """快速排序""" | ||||
|     def quick_sort(self, nums, left, right): | ||||
|         # 子数组长度为 1 时终止递归 | ||||
|         if left >= right: | ||||
|             return | ||||
|         # 哨兵划分 | ||||
|         pivot = self.partition(nums, left, right) | ||||
|         # 递归左子数组、右子数组 | ||||
|         self.quick_sort(nums, left, pivot-1) | ||||
|         self.quick_sort(nums, pivot+1, right) | ||||
|  | ||||
|  | ||||
| """快速排序类(中位基准数优化)""" | ||||
| class quick_sort_median(): | ||||
|  | ||||
|     # 选取三个元素的中位数 | ||||
|     def median_three(self, nums, left, mid, right): | ||||
|         # 使用了异或操作来简化代码 | ||||
|         # 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1 | ||||
|         if (nums[left] > nums[mid]) ^ (nums[left] > nums[right]): | ||||
|             return left | ||||
|         elif (nums[mid] < nums[left]) ^ (nums[mid] > nums[right]): | ||||
|             return mid | ||||
|         return right | ||||
|  | ||||
|     """哨兵划分(三数取中值)""" | ||||
|     def partition(self, nums, left, right): | ||||
|         # 以 nums[left] 作为基准数 | ||||
|         med = self.median_three(nums, left, (left+right)//2, right) | ||||
|         # 将中位数交换至数组最左端 | ||||
|         nums[left], nums[med] = nums[med], nums[left] | ||||
|         # 以 nums[left] 作为基准数 | ||||
|         i, j = left, right | ||||
|         while i < j: | ||||
|             while i < j and nums[j] >= nums[left]: | ||||
|                 j -= 1      # 从右向左找首个小于基准数的元素 | ||||
|             while i < j and nums[i] <= nums[left]: | ||||
|                 i += 1      # 从左向右找首个大于基准数的元素 | ||||
|             # 元素交换 | ||||
|             nums[i], nums[j] = nums[j], nums[i]  | ||||
|         # 将基准数交换至两子数组的分界线 | ||||
|         nums[i], nums[left] = nums[left], nums[i] | ||||
|         return i            # 返回基准数的索引 | ||||
|  | ||||
|     """快速排序""" | ||||
|     def quick_sort(self, nums, left, right): | ||||
|         # 子数组长度为 1 时终止递归 | ||||
|         if left >= right:return | ||||
|         # 哨兵划分 | ||||
|         pivot = self.partition(nums, left, right) | ||||
|         # 递归左子数组、右子数组 | ||||
|         self.quick_sort(nums, left, pivot-1) | ||||
|         self.quick_sort(nums, pivot+1, right) | ||||
|  | ||||
|  | ||||
| """快速排序类(尾递归优化)""" | ||||
| class quick_sort_tail_call(): | ||||
|  | ||||
|     """哨兵划分""" | ||||
|     def partition(self, nums, left, right): | ||||
|         # 以 nums[left] 作为基准数 | ||||
|         i, j = left, right | ||||
|         while i < j: | ||||
|             while i < j and nums[j] >= nums[left]: | ||||
|                 j -= 1   # 从右向左找首个小于基准数的元素 | ||||
|             while i < j and nums[i] <= nums[left]: | ||||
|                 i += 1   # 从左向右找首个大于基准数的元素 | ||||
|             # 元素交换 | ||||
|             nums[i], nums[j] = nums[j], nums[i] | ||||
|         # 将基准数交换至两子数组的分界线 | ||||
|         nums[i], nums[left] = nums[left], nums[i] | ||||
|         return i  # 返回基准数的索引 | ||||
|  | ||||
|     """快速排序(尾递归优化)""" | ||||
|     def quick_sort(self, nums, left, right): | ||||
|         # 子数组长度为 1 时终止 | ||||
|         while left < right: | ||||
|             # 哨兵划分操作 | ||||
|             pivot = self.partition(nums, left, right) | ||||
|             # 对两个子数组中较短的那个执行快排 | ||||
|             if pivot-left < right-pivot: | ||||
|                 self.quick_sort(nums, left, pivot-1)  # 递归排序左子数组 | ||||
|                 left = pivot+1  # 剩余待排序区间为 [pivot + 1, right] | ||||
|             else: | ||||
|                 self.quick_sort(nums, pivot+1, right)  # 递归排序右子数组 | ||||
|                 right = pivot-1  # 剩余待排序区间为 [left, pivot - 1] | ||||
|  | ||||
| if __name__ == '__main__': | ||||
|     # 快速排序  | ||||
|     nums = [4, 1, 3, 1, 5, 2] | ||||
|     quick_sort().quick_sort(nums, 0, len(nums)-1) | ||||
|     print("快速排序完成后 nums = ", nums) | ||||
|  | ||||
|     # 快速排序(中位基准数优化) | ||||
|     nums1 = [4, 1, 3, 1, 5, 2] | ||||
|     quick_sort_median().quick_sort(nums1, 0, len(nums1)-1) | ||||
|     print("快速排序(中位基准数优化)完成后 nums = ", nums) | ||||
|  | ||||
|     # 快速排序(尾递归优化) | ||||
|     nums2 = [4, 1, 3, 1, 5, 2] | ||||
|     quick_sort_tail_call().quick_sort(nums, 0, len(nums2)-1) | ||||
|     print("快速排序(尾递归优化)完成后 nums = ", nums) | ||||
|   | ||||
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