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add a code in go
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@ -38,31 +38,56 @@
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OK!我们到这一步就能把这个变种给整的明明白白的了,下面我们看一哈程序代码吧,也是非常简单的。
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Java Code:
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```java
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public static int lowBoundnum(int[] nums,int target,int left, int right) {
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while (left <= right) {
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//求中间值
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int mid = left + ((right - left) >> 1);
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//大于目标值的情况
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if (nums[mid] > target) {
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//返回 mid
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if (mid == 0 || nums[mid-1] <= target) {
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return mid;
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}
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else{
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right = mid -1;
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}
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} else if (nums[mid] <= target){
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left = mid + 1;
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while (left <= right) {
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//求中间值
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int mid = left + ((right - left) >> 1);
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//大于目标值的情况
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if (nums[mid] > target) {
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//返回 mid
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if (mid == 0 || nums[mid-1] <= target) {
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return mid;
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}
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else{
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right = mid -1;
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}
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} else if (nums[mid] <= target){
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left = mid + 1;
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}
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//所有元素都小于目标元素
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return -1;
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}
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//所有元素都小于目标元素
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return -1;
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}
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```
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Go Code:
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```go
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func lowBoundnum(nums []int, target, left, right int) int {
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for (left <= right) {
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//求中间值
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mid := left + ((right - left) >> 1);
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//大于目标值的情况
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if (nums[mid] > target) {
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//返回 mid
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if (mid == 0 || nums[mid-1] <= target) {
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return mid
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}else{
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right = mid -1
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}
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} else if (nums[mid] <= target){
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left = mid + 1
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}
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}
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//所有元素都小于目标元素
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return -1
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}
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```
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## **找出最后一个小于目标元素的索引**
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@ -73,6 +98,8 @@ public static int lowBoundnum(int[] nums,int target,int left, int right) {
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查找最后一个小于目标数的元素,比如我们的目标数为 7 ,此时他前面的数为 6,最后一个 6 的索引为 5,此时我们返回 5 即可,如果目标数元素为 12,那么我们最后一个元素为 11,仍小于目标数,那么我们此时返回 8,即可。这个变种其实算是上面变种的相反情况,上面的会了,这个也完全可以搞定了,下面我们看一下代码吧。
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Java Code:
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```java
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public static int upperBoundnum(int[] nums,int target,int left, int right) {
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@ -99,6 +126,7 @@ public static int upperBoundnum(int[] nums,int target,int left, int right) {
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```
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Go Code:
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```go
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func upperBoundnum(nums []int, target, left, right int) int {
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