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65 lines
1.4 KiB
Markdown
65 lines
1.4 KiB
Markdown
### leetcode35搜索插入位置
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#### 题目描述
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> 给定一个排序数组和一个目标值,在数组中找到目标值,并返回其索引。如果目标值不存在于数组中,返回它将会被按顺序插入的位置。
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>
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> 你可以假设数组中无重复元素。
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示例 1:
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> 输入: [1,3,5,6], 5
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> 输出: 2
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示例 2:
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> 输入: [1,3,5,6], 2
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> 输出: 1
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示例 3:
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> 输入: [1,3,5,6], 7
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> 输出: 4
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示例 4:
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> 输入: [1,3,5,6], 0
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> 输出: 0
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#### 题目解析
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这个题目完全就和咱们的二分查找一样,只不过有了一点改写,那就是将咱们的返回值改成了 left,具体实现过程见下图
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![搜索插入位置](https://img-blog.csdnimg.cn/img_convert/d806cb5199c4baeebc62bebe29d7eded.gif)
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#### 题目代码
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```java
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class Solution {
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public int searchInsert(int[] nums, int target) {
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int left = 0, right = nums.length-1;
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//注意循环条件
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while (left <= right) {
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//求mid
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int mid = left + ((right - left ) >> 1);
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//查询成功
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if (target == nums[mid]) {
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return mid;
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//右区间
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} else if (nums[mid] < target) {
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left = mid + 1;
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//左区间
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} else if (nums[mid] > target) {
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right = mid - 1;
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}
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}
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//返回插入位置
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return left;
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}
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}
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```
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